NCERT Class 10 Maths Chapter 5 Exercise 5.1 Question 2(a)

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📚 Question 2(a)

Write first four terms of the AP, when the first term \(a\) and the common difference \(d\) are given as follows:

\(a = 10\), \(d = 10\)

📌 Given Information

  • First term: \(a = 10\)
  • Common difference: \(d = 10\)
  • We need to find the first four terms of the AP

🎯 To Find

The first four terms of the Arithmetic Progression: \(a_1, a_2, a_3, a_4\)

💡 Key Concept

Arithmetic Progression (AP): A sequence where each term is obtained by adding a fixed number (common difference) to the previous term.

General Form:

\[a, a+d, a+2d, a+3d, \ldots\]

nth Term Formula:

\[a_n = a + (n-1)d\]

✍️ Step-by-Step Solution

Step 1: Identify the given values

Step 2: Calculate each term using the formula

Using the formula \(a_n = a + (n-1)d\):

First term (\(n = 1\)):

\(a_1 = a = 10\)

Second term (\(n = 2\)):

\(a_2 = a + (2-1)d\)

\(a_2 = 10 + (1)(10)\)

\(a_2 = 10 + 10 = 20\)

Third term (\(n = 3\)):

\(a_3 = a + (3-1)d\)

\(a_3 = 10 + (2)(10)\)

\(a_3 = 10 + 20 = 30\)

Fourth term (\(n = 4\)):

\(a_4 = a + (4-1)d\)

\(a_4 = 10 + (3)(10)\)

\(a_4 = 10 + 30 = 40\)

Step 3: Verify the common difference

Check that the difference between consecutive terms is constant:

\(a_2 – a_1 = 20 – 10 = 10\) ✓

\(a_3 – a_2 = 30 – 20 = 10\) ✓

\(a_4 – a_3 = 40 – 30 = 10\) ✓

Verification: All differences equal 10, confirming this is a valid AP.

✅ Final Answer

The first four terms of the AP are:

\[10, 20, 30, 40\]

📊 Visual Representation

Term 1
10
+10 →
Term 2
20
+10 →
Term 3
30
+10 →
Term 4
40

Pattern: Each term increases by 10

🔄 Alternative Method: Direct Addition

Instead of using the formula, we can simply add the common difference repeatedly:

Start with \(a_1 = 10\)

\(a_2 = a_1 + d = 10 + 10 = 20\)

\(a_3 = a_2 + d = 20 + 10 = 30\)

\(a_4 = a_3 + d = 30 + 10 = 40\)

Note: Both methods give the same result. Use whichever is more convenient!

🔍 Properties of This AP

PropertyValue
First term (a)10
Common difference (d)10
Type of APIncreasing (d > 0)
General term formula\(a_n = 10n\)
10th term\(a_{10} = 10 + 9(10) = 100\)

⚠️ Common Mistakes to Avoid

  1. Starting from \(n = 0\): The first term corresponds to \(n = 1\), not \(n = 0\).
  2. Forgetting to multiply by \((n-1)\): The formula is \(a + (n-1)d\), not \(a + nd\).
  3. Confusing \(a\) and \(d\): Make sure to identify which is the first term and which is the common difference.
  4. Not verifying: Always check that consecutive differences are equal to confirm it’s an AP.

📝 Practice Problems

  1. Find the first 6 terms of the AP with \(a = 10\) and \(d = 10\).
  2. What is the 20th term of this AP?
  3. If the first term is 10 and the 5th term is 50, find the common difference.
  4. Find the sum of the first four terms: \(10 + 20 + 30 + 40 = ?\)
Farhan Mansuri

Written by Farhan Mansuri

M.Sc. Mathematics | B.Ed. | 15+ Years Teaching Experience

Farhan Mansuri is a dedicated mathematics educator with over 15 years of experience teaching CBSE curriculum. He specializes in making complex mathematical concepts accessible to Class 10 students.

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